
The heat of combustion of liquid borazine has been determined according to the following equation: B 3 N 3 H 6 ( liq ) + 15 / 4 O 2 ( g ) + 3 / 2 H 2 O ( liq ) = 3 H 3 BO 3 ( c ) + 3 / 2 N 2 ( g ) , Δ H ° ( 25 ° C ) = - 2313.3 ± 12.6 kj / mole ( - 552.90 ± 3.0 kcal / mole ) . From this value the heat of formation of liquid borazine may be calculated as ΔHf°(25 °C) = -548.5 ± 13.4 kj/mole (-131.1 ± 3.2 kcal/mole), and for the gas, ΔHf°(25 °C) = -519.2 ± 13.4 kj/mole (-124.1 ± 3.2 kcal/mole).
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