
arXiv: 1012.5320
handle: 11583/2440618
By an elementary approach, we derive the value of the Gauss sum of a cubic character over a finite field F2s without using Davenport–Hasse's theorem (namely, if s is odd the Gauss sum is −1, and if s is even its value is −(−2)s/2).
10123 Institute of Mathematics, 510 Mathematics, Mathematics - Number Theory, Gauss sum; character; binary finite fields, FOS: Mathematics, Number Theory (math.NT)
10123 Institute of Mathematics, 510 Mathematics, Mathematics - Number Theory, Gauss sum; character; binary finite fields, FOS: Mathematics, Number Theory (math.NT)
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