
doi: 10.1090/proc/14753
The objective of this paper is to investigate operator functions by making use of the operator harmonic mean ‘ ! \,!\, ’. For 0 > A ≦ B 0>A\leqq B , we construct a unique pair X X , Y Y such that 0 > X ≦ Y , A = X ! Y , B = X + Y 2 0>X\leqq Y, \; A=X\,!\,Y,\; B=\frac {X+Y}{2} . We next give a condition for operators A , B , C ≧ 0 A, B, C\geqq 0 in order that C ≦ A ! B C \leqq A\,!\ B and show that g ≠ 0 g\ne 0 is strongly operator convex on J J if and only if g ( t ) > 0 g(t)>0 and g ( A + B 2 ) ≦ g ( A ) ! g ( B ) g (\frac {A+B}{2}) \leqq g(A)\,!\,g(B) for A , B A, B with spectra in J J . This inequality particularly holds for an operator decreasing function on the right half line. We also show that f ( t ) f(t) defined on ( 0 , b ) (0, b) with 0 > b ≦ ∞ 0>b\leqq \infty is operator monotone if and only if f ( 0 + ) > ∞ , f ( A ! B ) ≦ 1 2 ( f ( A ) + f ( B ) ) f(0+)>\infty , \;f (A\,!\,B)\leqq \frac {1}{2}(f(A) + f(B)) . In particular, if f > 0 f>0 , then f f is operator monotone if and only if f ( A ! B ) ≦ f ( A ) ! f ( B ) f (A\, !\, B) \leqq f(A)\, !\, f(B) . We lastly prove that if a strongly operator convex function g ( t ) > 0 g(t)>0 on a finite interval ( a , b ) (a, b) is operator decreasing, then g g has an extension g ~ \tilde {g} to ( a , ∞ ) (a, \infty ) that is positive and operator decreasing.
Functional calculus for linear operators, Linear inequalities of matrices, Loewner theorem, Linear operator inequalities, operator monotone functions, strongly operator convex functions, Convexity of real functions in one variable, generalizations, operator harmonic mean
Functional calculus for linear operators, Linear inequalities of matrices, Loewner theorem, Linear operator inequalities, operator monotone functions, strongly operator convex functions, Convexity of real functions in one variable, generalizations, operator harmonic mean
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