Let $N$ be a positive integer and let $J_0(N)$ be the Jacobian variety of the modular curve $X_0(N)$. For any prime $p\ge 5$ whose square does not divide $N$, we prove that the $p$-primary subgroup of the rational torsion subgroup of $J_0(N)$ is equal to that of the rational cuspidal divisor class group of $X_0(N)$, which is explicitly computed in \cite{Yoo9}. Also, we prove the same assertion holds for $p=3$ under the extra assumption that either $N$ is not divisible by $3$ or there is a prime divisor of $N$ congruent to $-1$ modulo $3$.

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