
doi: 10.1007/bf01202099
Let \(T\) be a bounded linear operator defined on a separable, infinite dimensional Banach space \(X\). If there is an \(x\in X\) for which \(\{T^nx\}_{n=0}^{\infty}\) is dense in \(X\), then \(x\) is a hypercyclic vector and \(T\) is a hypercyclic operator. An infinite dimensional, closed linear subspace, \(H \subseteq X\), is hypercyclic if every \(x\in H\) is hypercyclic. \textit{A. Montes-Rodriguez} [Mich. Math. J. 43, No.~3, 419--436 (1996; Zbl 0907.47023)] proved a sufficient condition for \(T\) to admit a hypercyclic subspace. The proof is technical. This work provides a more elementary proof of this basic result. The proof relies on properties of the algebra of bounded linear operators on \(X\).
operator algebra, hypercyclic vector, Cyclic vectors, hypercyclic and chaotic operators, dense orbits, Transformers, preservers (linear operators on spaces of linear operators), Classical Banach spaces in the general theory
operator algebra, hypercyclic vector, Cyclic vectors, hypercyclic and chaotic operators, dense orbits, Transformers, preservers (linear operators on spaces of linear operators), Classical Banach spaces in the general theory
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