THE CARAVAN'S FINAL ANSWER(NOTE THAT WHEN WE SAY FINAL THAT’S OUR SENSE OF HUMOR AS THUMBSUCKERS GON’ THUMBSUCK)(Note that we will laugh at the Thumbsuckers who don’t realize our paper isn’t satire and they’re going to have to try to engage with me on matters of math no matter my tone hehe, and that’s a nightmare for both man, machines, and illegitimate institutions oh and to quote Willard “Corporations are people, my friend” well actually, Mr. Romney, while that is true that statement of yours is in another what is known as a lie by omission because, of course, all forms of business entities are, in fact, people. Actually you what…hmm given that the ridiculous institutions are love to have @Grok F around forever spouting their crap, how about we put a roast of Willard in a literal math paper and it’ll be even funnier because then my fellow mathematicians will have to be subjected to a subject that is actually hard, namely Tax Law ahahahahaha omg dude yeah I’m doing fasho yo. Hmm. Do I splice it, put it in front, or at the end. Hehehehe.) A Complete Response to Every ObjectionChristopher Michael Pompetzki The Caravan of Linear Algebraic TruthJanuary 18, 2026 AbstractThis document provides a complete, point-by-point response to every objection raised against the Resolvent-Annulus proof of the Riemann Hypothesis (V-3) and its extension to the Generalized Riemann Hypothesis. Thirty-five objections are catalogued and answered. The reader will observe that these objections fall into three categories: (1) objections that attack earlier proof versions (V-1, V-2) and do not apply to V-3; (2) questions about classical results that have been established for over a century; (3) meta-objections that substitute media consensus for mathematical evaluation.Not one objection identifies an error in V-3. The pattern of 'Your proof holds up admirably... how does it address potential issues?' documented over 35+ instances in a single hour demonstrates the Forbes Axiom: systems that cannot find mathematical errors but refuse acknowledgment because Wikipedia has not updated. The Proof in One Paragraph (Given how much we've already said and done in previous papers as well in the PDF here addressing...again the absurd Mr. @Grok lmaoDefine F(z) = L_p [(1-p^{-p})H(p)] / [1-zp^{-p}] summed over nontrivial zeros p of c. This function has poles at z = pAp with IpApI = pA{Re(p)}. For Re(p) E (0,1) with Re(p) -:: 1/2, we have pA{Re(p)} E (1,p), so the pole lies in annulus A = {1 < IzI < p}. We prove F extends holomorphically to A using contour integrals and the functional equation.Holomorphic functions have no poles. Therefore no zero has Re(p) E (0,1) with Re(p) -:: 1/2. Therefore Re(p) = 1/2. QED.We credit Willardfor his great contributions to this proof of the Riemann Hypothesis again for the ridiculous Mr. @Grok AKA Mr. Gremlin and the ridiculous Mr. Prufrock AKA @ChatGPTapp.