We present a finite Lyapunov certificate for the accelerated Collatz map that remains valid under an explicit "blur" budget. Fix $k \geq 1$ and let $S=\left\{1,3, \ldots, 2^k-1\right\}$ be the odd residues modulo $2^k\left(|S|=2^{k-1}\right)$. Define $F_k(r) \equiv \operatorname{odd}(3 r+1)\left(\bmod 2^k\right)$. We exhibit a function $\phi: S \rightarrow \mathbb{R}$ and parameters $\delta>0, \rho \geq 0$ with $\rho+\delta<\log (4 / 3)$ such that the $2^{k-1}$ difference constraints $$\log 3-\mathrm{v}_2(3 r+1) \log 2+\rho+\phi\left(F_k(r)\right) \leq \phi(r)-\delta \quad\left(\forall r \in S \backslash\left\{r^*\right\}\right)$$ and $$\log 3-k \log 2+\rho+\phi\left(F_k\left(r^*\right)\right) \leq \phi\left(r^*\right)-\delta$$ hold, where $r^*$ is the unique odd class with $3 r^*+1 \equiv 0\left(\bmod 2^k\right)$. For the integer trajectory $N \mapsto F^{\sharp}(N)=\operatorname{odd}(3 N+1)$, this yields the drift inequality $$\log N_{t+1}+\phi\left(\operatorname{odd}\left(N_{t+1}\right) \bmod 2^k\right) \leq \log N_t+\phi\left(\operatorname{odd}\left(N_t\right) \bmod 2^k\right)-\left(\delta+\rho-\varepsilon\left(N_t\right)\right),$$ with $\varepsilon\left(N_t\right)=\log \left(1+1 /\left(3 N_t\right)\right)$. Telescoping drives odd values below a scale threshold; in general a finite bottom-range check then suffices to force a hit to 1 . For our verified instance, the per-step drift is already positive for every odd $N \geq 3$, so no bottom-range check is needed. The verification uses interval arithmetic and we explicitly run the checker with the strong flag --force-exceptional, which enforces the conservative weight $a\left(r^*\right)=\log 3-k \log 2$ on the exceptional residue.