
doi: 10.1137/0405039
Let \(G\) be a bridgeless graph with \(n\) vertices and \(m\) edges and let \(r\) be the minimum length of an even cycle in \(G\) of length at least 6 \((r=\infty\) if there is no such cycle). It is proved that the edges of \(G\) can be covered by cycles whose total length is at most \(m+(n-1)r/(r- 1)\). The proof suggests a polynomial time algorithm for constructing such a cover.
Eulerian and Hamiltonian graphs, Eulerian subgraph, Edge subsets with special properties (factorization, matching, partitioning, covering and packing, etc.), polynomial time algorithm, Paths and cycles, cycle cover
Eulerian and Hamiltonian graphs, Eulerian subgraph, Edge subsets with special properties (factorization, matching, partitioning, covering and packing, etc.), polynomial time algorithm, Paths and cycles, cycle cover
| selected citations These citations are derived from selected sources. This is an alternative to the "Influence" indicator, which also reflects the overall/total impact of an article in the research community at large, based on the underlying citation network (diachronically). | 21 | |
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| influence This indicator reflects the overall/total impact of an article in the research community at large, based on the underlying citation network (diachronically). | Top 10% | |
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