We consider an asynchronous voting process on graphs which we call discordant voting, and which can be described as follows. Initially each vertex holds one of two opinions, red or blue say. Neighbouring vertices with different opinions interact pairwise. After an interaction both vertices have the same colour. The quantity of interest is T, the time to reach consensus , i.e. the number of interactions needed for all vertices have the same colour. An edge whose endpoint colours differ (i.e. one vertex is coloured red and the other one blue) is said to be discordant. A vertex is discordant if its is incident with a discordant edge. In discordant voting, all interactions are based on discordant edges. Because the voting process is asynchronous there are several ways to update the colours of the interacting vertices. Push: Pick a random discordant vertex and push its colour to a random discordant neighbour. Pull: Pick a random discordant vertex and pull the colour of a random discordant neighbour. Oblivious: Pick a random endpoint of a random discordant edge and push the colour to the other end point. We show that E(T), the expected time to reach consensus, depends strongly on the underlying graph and the update rule. For connected graphs on n vertices, and an initial half red, half blue colouring the following hold. For oblivious voting, E(T) =n^2/4 independent of the underlying graph. For the complete graph K_n, the push protocol has E(T)= Theta(n log(n)), whereas the pull protocol has E(T)= Theta(2^n). For the cycle C_n all three protocols have E(T) = Theta(n^2). For the star graph however, the pull protocol has E(T)=O(n^2), whereas the push protocol is slower with E(T) = Theta(n^2 log(n)). The wide variation in E(T) for the pull protocol is to be contrasted with the well known model of synchronous pull voting, for which E(T) = O(n) on many classes of expanders.