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doi: 10.5281/zenodo.2588891 , 10.5281/zenodo.2588892 , 10.5281/zenodo.2596331 , 10.5281/zenodo.2595696 , 10.5281/zenodo.2598772 , 10.5281/zenodo.2597704 , 10.5281/zenodo.2596354 , 10.5281/zenodo.2594093 , 10.5281/zenodo.2593729 , 10.5281/zenodo.2589001 , 10.5281/zenodo.2589813 , 10.5281/zenodo.2596013
doi: 10.5281/zenodo.2588891 , 10.5281/zenodo.2588892 , 10.5281/zenodo.2596331 , 10.5281/zenodo.2595696 , 10.5281/zenodo.2598772 , 10.5281/zenodo.2597704 , 10.5281/zenodo.2596354 , 10.5281/zenodo.2594093 , 10.5281/zenodo.2593729 , 10.5281/zenodo.2589001 , 10.5281/zenodo.2589813 , 10.5281/zenodo.2596013
P versus NP is considered as one of the great open problems of science. This consists in knowing the answer of the following question: Is P equal to NP? This problem was first mentioned in a letter written by John Nash to the National Security Agency in 1955. However, a precise statement of the P versus NP problem was introduced independently by Stephen Cook and Leonid Levin. Since that date, all efforts to find a proof for this problem have failed. Another major complexity class is coNP. Whether NP = coNP is another fundamental question that it is as important as it is unresolved. We prove there is a problem in coNP that is not in P. In this way, we show that P is not equal to coNP. Since P = NP implies P = coNP, then we also demonstrate that P is not equal to NP.
Archived previous version in https://hal.archives-ouvertes.fr/hal-01509423
coNP-complete, coNP, P, Minimum, Boolean circuit, NP
coNP-complete, coNP, P, Minimum, Boolean circuit, NP
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