26 references, page 1 of 3 [S(x) − S(η)] M (dη), Σ(l) := [M (x) − M (η)] dS(η) π(y) Π(x) −1 M (y) M (y) s(y) dy. s(y)M (y) dy − s(y)M (y) dy < ∞ − M (y) dy s(y)[M (y) − M (x)] dy = Σ(1) = ∞ s(y) M (y) − M (1) s(y)[M (1) − M (y)] dy = N (1) < ∞. A − α A − Proof. Let f ∈ F [0, 1]. By Remark 3.12, we have for all t > 0 that (Πt, f ) = (Πt∗, Λf ). Therefore, writing Rt = dΠt/dΠ as usual, we have Z Z 1 + c2λn,1tn

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